{"operation":"document","citation":"PI-92-063","title":"Georgia Public Service Commission — Pipeline Safety Interpretation","source_type":"guidance","agency":"Pipeline and Hazardous Materials Safety Administration","status":"guidance","official":true,"published_on":"1992-12-09","effective_on":null,"summary":"PI-92-063 response to Georgia Public Service Commission concerning 199.7.","machine_formats":{"json":"https://regulus.evalyn.ai/document/phmsa-interpretation-pi-92-063.json","markdown":"https://regulus.evalyn.ai/document/phmsa-interpretation-pi-92-063.md"},"app_url":"https://regulus.evalyn.ai/document/phmsa-interpretation-pi-92-063","source_url":"https://www.phmsa.dot.gov/sites/phmsa.dot.gov/files/legacy/interpretations/Interpretation%20Files/Pipeline/1992/PI92063.pdf","body":"<<<PAGE 1>>>\n\nDecember 9, 1992\nMr. R. Lynnard Tessner\nDirector, Office of Pipeline Safety\nGeorgia Public Service Commission\n244 Washington Street, S.W.\natlanta, GA 30334-5701\nDear Mr. Tessner:\nThis is in response to your correspondence dated October 6, 1992,\nrequesting this office's evaluation of a random selection process\nwhich could be used by a large number of small gas systems in the\nState of Georgia.\nYou outline a procedure which sets forth random testing options for\nsmall gas systems whose employee population ranges from one to\nseven employees. The procedure provides for quarterly testing at a\ntesting rate of 50 percent. For ease of explaining you indicate\nthat slips of paper with employee names would be placed in a hat.\nIf there are seven or fewer employees in the random pool, add\nenough blank slips with the name slips in the hat to total eight\nslips of paper.\nYour procedures for testing are outlined below:\n1. With seven employees add one slip and pull sample from hat\nfour times a year. On each sample pull, each employee will\nhave 1/8 chance of being selected. Since there are seven\nemployees that makes a 7/8 chance that an employee would be\nselected. If four selections are chosen per year on an\naverage 7/8 x 4 = 3.5 employees will selected and tested which\nwould equal 50 percent.\n2. With six employees add two slips and pull sample from hat four\ntimes a year. On each sample pull, each employee will have a\n1/8 chance of being selected. Since there are six employees\nthat makes a 6/8 chance that an employee would be selected.\nIf four selections are chosen per year on an average 6/8 x 4 =\n3 employees will be selected and tested which would equal 50\npercent.\n3. With five employees add three slips and pull sample from hat\nfour times a year. On each sample pull, each employee will\nhave a 1/8 chance of being selected. Since there are five\nemployees that makes a 5/8 chance that an employee would be\nselected. If four selections are chosen per year on an\naverage 5/8 x 4 = 2.5 employees will be selected and tested\nwhich would equal 50 percent.\n4. With four employees add four slips and pull sample from hat\nfour times a year. On each sample pull, each employee will\n\n<<<PAGE 2>>>\n\n5. 6. 7. have 1/8 chance of being selected. Since there are four\nemployees that makes a 4/8 chance that an employee would be\nselected. If four selections are chose per year on an average\n4/8 x 4 = 2 employees will be selected and tested which would\nequal 50 percent.\nWith three employees add five slips and pull sample from hat\nfour times a year. On each sample pull, each employee will\nhave a 1/8 chance of being selected. Since there are three\nemployees that makes a 3/8 chance that an employee would be\nselected. If four selections are chosen per year on an\naverage 3/8 x 4 = 1.5 employees will be selected and tested\nwhich would equal 50 percent.\nWith two employees add six slips and pull sample from hat four\ntimes a year. On each sample pull, each employee will have a\n1/8 chance of being selected. Since there are two employees\nthat makes a 2/8 chance that an employee would be selected.\nIf four selections are chosen per year on an average 2/8 x 4 =\n1 employee will be selected and tested which would equal 50\npercent.\nWith one employee add seven slips and pull sample from hat\nfour times a year. On each sample pull, each employee will\nhave a 1/8 chance of being selected. Since there is one\nemployee that makes a 1/8 chance that an employee would be\nselected. If four selections are chosen per year on an\naverage 1/8 x 4= 1/2 or 1 employee will be selected and tested\nwhich would equal 50 percent.\nIt would appear that the procedure you have presented may be\nfeasible for small gas systems and would meet the intent of\nconducting random testing as outlined in Section 199.11(c).\nThank you for your inquiry. Please let me know if you need any\nadditional information about our drug testing requirements.\nSincerely,\nRichard L. Rippert\nDrug Compliance Coordinator\nOffice of Pipeline Safety\nEnforcement","truncated":false,"body_characters":4018}